9. the sum of the digits of a two digit number is 8. if 36 is added to the number the digits interchange their places. find the number
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let the digit in units place be x
digit in thens place = 8 - x
the original number = 10(8-x) + x
=80-9x
the reversed number= 10x + (8-x)
= 9x + 8
according to the condition,
80 - 9x +36 = 9x + 8
108=18x
x = 6
therefore, the original number is 80 -9(6)
80- 54
26
digit in thens place = 8 - x
the original number = 10(8-x) + x
=80-9x
the reversed number= 10x + (8-x)
= 9x + 8
according to the condition,
80 - 9x +36 = 9x + 8
108=18x
x = 6
therefore, the original number is 80 -9(6)
80- 54
26
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