Question

9. The sum of three consecutive integers is 108. What are the
integers?

Answer 1

Answer:

x

x+1

x+2

Let above 3 will be three consecutive integers

x+x+1+x+2=108

3x+3=108

3x=108-3

3x=105

x=105/3

x=35

x+1=35+1=36

x+2=35+2=37

so the three consecutive integers are 35,36,37

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Answer 2

$\rule{400}4$

☆ ANSWER:-

▪︎ Given:-

• The sum of three consecutive integers = 108.

▪︎ To Find:-

• The integers.

$\rule{400}2$

▪︎ So,

• Let the integers be x, x+1 and x+2.

$\rule{400}2$

▪︎ Thus, ATQ:-

$\tt\mapsto(x) + (x + 1) + (x + 2) = 108 \\ \\ \tt\mapsto \: x + x + 1 + x + 2 = 108 \\ \\ \tt\mapsto \: 3x + 3 = 108 \\ \\ \tt\mapsto3x = 108 - 3 \\ \\ \tt\mapsto3x = 105 \\ \\ \tt\mapsto \: x = \cancel\frac{105}{3} \\ \\ \tt\large\red{\fbox{\mapsto \: x = 35}}$

$\rule{400}2$

▪︎ Therefore Integers are:-

• x = 35.

• x+1 = 35+1 = 36.

• x+2 = 35+2 = 37.

$\rule{400}4$

${\small{\green{\boxed{\bold{\sf{\therefore{Consecutive \:integers\:are\:35,\:36\:And\:37.}}}}}}}$

$\rule{400}4$

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$\rule{400}4$