Question

9: The sum of three consecutive multiples of 11 is 363
find these multiple ​

Answer 1

Let the 3 consecutive multiples of 11 be x-11,x,x+11

ATQ, x-11+x+x+11=363

or, 3x=363

or, x= 363÷3= 121

Therefore the multiples are,

121,

121-11=110

121+11=132