Question

9. The sum of two numbers is 80. The larger number exceeds four times the smaller one by 5. Find the larger number.*

Answer 1

Step-by-step explanation:

Let the smaller one be X

then the Larger one be 4X+5

A/C

X+4X+5=80

5X+5=80

5X=75

X=75/5

X=15

THEN

• X=15
• 4X+5=4*15+5=65

HENCE THE TWO NUMBERS ARE 65 AND 15

I HOPE THAT THIS WOULD HELP YOU

MARK AS BRSINLIEST

Answer 2

Solution :

Let the smaller number be r & greater number be m;

A/q

$\underbrace{\sf{1^{st}\:Case\::}}}$

$\longrightarrow\sf{r+m=80}\\\\\longrightarrow\sf{r=80-m........................(1)}$

$\underbrace{\sf{2^{nd}\:Case\::}}}$

$\longrightarrow\sf{m=4r+5}\\\\\longrightarrow\sf{m-4r=5}\\\\\longrightarrow\sf{m-4(80-m)=5\:\:\:[from(1)]}\\\\\longrightarrow\sf{m-320+4m=5}\\\\\longrightarrow\sf{5m-320=5}\\\\\longrightarrow\sf{5m=5+320}\\\\\longrightarrow\sf{5m=325}\\\\\longrightarrow\sf{m=\cancel{325/5}}\\\\\longrightarrow\bf{m=65}$

Putting the value of m in equation (1),we get;

$\longrightarrow\sf{r=80-65}\\\\\longrightarrow\bf{r=15}$

Thus;

The larger number will be 65 .