9. The surface area of a cuboid is 468 cm². Its length and breadth are 12 cm and 9 cm respectively
Find its height.
Answers
Given :–
- Surface area of a cuboid = 468cm²
- Length of a cuboid (l) = 12cm
- Breadth of a cuboid (b) = 9cm
To Find :–
- Height of a cuboid.
Solution :–
Let, the height of a cuboid be x.
We know that,
Surface area of a cuboid = 2(lb + bh + hl)
- l = 12cm
- b = 9cm
Now, put the given values in the formula of surface area of a cuboid.
⟹ 468cm² = 2[(12)(9) + (9)(x) + (x)(12)]
Open the small brackets.
⟹ 468cm² = 2[108 + 9x + 12x]
⟹ 468cm² = 2[108 + 21x]
Now, open the large bracket.
⟹ 468cm² = 216 + 42x
⟹ 468 – 216 = 42x
⟹ 252 = 42x
⟹ = x
Cut the denominator and the numerator by 2, we obtain
⟹ = x
Cut the denominator and the numerator by 3, we obtain
⟹ = x
Cut the denominator and the numerator by 7, we obtain
⟹ 6 = x
Hence,
Height of a cuboid is 6cm.
Check :–
Surface area = 2(lb + bh + hl)
- Surface area of a cuboid = 468cm²
- Length of a cuboid = 12cm
- Breadth of a cuboid = 9cm
- Height of a cuboid = 6cm
Now, put all the values in the formula of surface area of a cuboid.
⟹ 2[(12)(9) + (9)(6) + (6)(12)]
Now, solve the small brackets.
⟹ 2[108 + 54 + 72]
⟹ 2[234]
Now, open the large bracket.
⟹ 468cm²
The surface area of a cuboid is equal to the given surface area value. So, the answer is correct.
Answer:
6 cm
Step-by-step explanation:
length = 12cm
breadth =9cm
height = ?
surface area of cuboid = 468cm²
2*( lb+bh+hl) = 468cm²
2*( 12 +9+9+h+h+12) =468cm²
2*( 21+9h+12h)= 468cm²
108+21h = 468/2
21 h = 234 - 108
21h = 126
h = 126/21
h =6cm