9.The taxi fare in a city as follows: for the first kilometre, the fare is 25and for the subsequent distance it is 14 per km. Taking the distancecovered as.x km and total fare as y,
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0
Total fare is y
Fare for first km is 25
Rate per km after first km is 14
So the equation formed is
y=25+14(x-1)
Since x distance also includes the first km
Fare for first km is 25
Rate per km after first km is 14
So the equation formed is
y=25+14(x-1)
Since x distance also includes the first km
Answered by
1
the equation is 14(x-1)25=y
Step-by-step explanation:
if X=0
then
14(0-1)25=y
0-14+25=y
y=11.
in this way with the help of the equation u can write subsequent points .
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