Question

9.
The total number of 9 digit numbers which have all different digits is
(A) 10!
(B) 9!
(C) 9x 9!
(D) 10x10

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Answer 1

Answer:

C

Step-by-step explanation:

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Answer 2

Answer:

(c) We have to form 9-digit number which has all different digit.

First digit from the left can be filled in 9 ways (excluding ‘0’).

Now nine digits are left including ‘O’.

So remaining eight places can be filled with these nine digits in 9PS ways.

So, total number of numbers = 9 x 9P8 = 9×9!