9. The vapour pressure of water at 20 0
C is
17 mm Hg. What is the vapour pressure
of solution containing 2.8 g urea in 50 g of
water?
Answers
Answered by
2
ANSWER
Vapour pressure of water= P
1
o
=17mmHg
Weight of water= W
1
=50g
Weight of urea= W
2
=2.8g
Molar mass of water= M
1
=18g/mol⇒n
1
=
18
50
=2.78
Molar mass of water= M
2
=60g/mol⇒n
2
=
60
2.8
=0.047
∴ Vapour pressure of solution P
1
P
1
o
P
1
o
−P
1
=
n
2
+n
1
n
2
⇒
17
17−P
1
=
2.78+0.047
0.047
=0.0166
⇒P
1
=16.71mmHg
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