Question

9. The vertex angle of an isosceles triangle measures 20 degrees more

than twice the measure of one of its base angles. What is the measure

of the base angle of this triangle?​

Answer 1

Step-by-step explanation:

let the equal angle of the isosceles triangle be x

the vertex angle is 2x + 20

sum of all angles of triangle is 180

x + x + 2x + 20 = 180

4x + 20 = 180

4x = 180 - 20

4x = 160

x = 160/4

x = 40°

the equal angle are 40° and 40°

the vertex angle = 2x + 20 = 2(40) + 20 = 80 + 20 = 100°

the three angles are

40°, 40°, 100°

hope you get your answer

Answer 2

The measure of the base angle of an isosceles triangle is 40°.

Given:

Vertex angle of an isosceles triangle = 20 degrees more than twice the measure of one of its base angles.

To find: The measure of the base angle of this triangle

Solution:

As we know, the base angles of an isosceles triangle are equal, and the sum of all the angles of a triangle is 180.

Let the base angle of the isosceles triangle be x, and the vertex angle is (2x + 20).

x + x + 2x + 20 = 180°

4x + 20° = 180°

4x = 180°  - 20°

4x = 160°

$x = \frac{160}{4}$

x = 40°

Base angles are 40°.

Vertex angle = 2x + 20 = 2(40) + 20 = 80 + 20 = 100°

Hence, the measure of the base angle of an isosceles triangle is  40°.

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