Question

9. The volume occupied by oxygen at STP
obtained on heating the 490 g of KClO3 is 130
L. Calculate the percentage purity of KClO3
(KCIO3 on heating produces KCl and O2).
​

Answer 1

Correct option is

D

3.36 L

The chemical equation for decomposition of KClO3 can be written as:

2KClO3→2KCl+3O2

245 g of KClO3 gives 67.2 L of O2 at STP.

12.25 g of KClO3 gives 24567.2×12.25 =3.36 L.

Hence, option D is correct.