Question

9. The volumes of IM HCl and 5M HCI moi
mixed to get 2 lit of 2M HCl are
1) 1 lit and 1 lit
2) 1.5 lit and 0.51
3) 1.25 lit and 0.75 lit 4) 1.33 lit and 0.66​

Answer 1

Final answer: The correct answer is option ($2$) $1.5$ $L$ and $0.5$ $L$.

Given that: We are given $1$ $M$ $HCl$ and $5$ $M$ $HCl$ are mixed to get $2$ $L$ of $2$ $M$ $HCl$.

To find: We have to find the volumes of $1$ $M$ $HCl$ and 5 M $HCl$ are mixed to get $2$ $L$ of $2$ $M$ $HCl$.

Explanation:

• Molarity of first $HCl$ solution ($M_{1}$) =  $1$ $M$

• The volume of first $HCl$ solution ($V_{1}$) = $?$

• Molarity of second $HCl$ solution ($M_{2}$) = $5$ $M$

• The volume of second $HCl$ solution ($V_{2}$) = $?$

• Molarity of mixture containing $1$ $M$ $HCl$ and $5$ $M$ $HCl$, $M$ = $2$ $M$

• The volume of mixture containing $1$ $M$ $HCl$ and $5$ $M$ $HCl$, $V$ = $2$ $L$

• Let $V_{1} = x$

$V_{2} = V - x = 2 - x$

• By conservation law, $MV=M_{1}V_{1} + M_{2}V_{2}$

Substitute the values: $2 \times 2 = (1 \times x) + 5(2-x)$

$4 = x +10 -5x\\\\4 =10 - 4x\\\\4x =10-6\\\\4x = 6\\\\x = \frac{6}{4} =1.5\\\\V_{1} = x =1.5\\\\V_{2} = 2 - x = 2 - 1.5 = 0.5$

The volume of first $HCl$ solution ($V_{1}$) = $1.5$ $L$

The volume of second $HCl$ solution ($V_{2}$) = $0.5$ $L$

• Hence, the correct answer is option ($2$) $1.5$ $L$ and $0.5$ $L$

• Substitute given data in the law of conservation:

$MV=M_{1}V_{1} + M_{2}V_{2}$

We get $V_{1}=1.5$ $L$  and $V_{2} =0.5$ $L$

Therefore, option ($1$) $1$ $L$  and $1$ $L$ , option ($3$) $1.25$ $L$  and $0.75$ $L$ , and option ($4$) $1.33$ $L$ and $0.66$ $L$ , are wrong answers.

To know more about the concept please go through the links

https://brainly.in/question/7794696

https://brainly.in/question/4775883

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