9. The walls and ceiling of a room are to be plastered. The length, breadth
and height of the room are 9 m, 6 m and 4 m respectively. Find the cost of
plastering at the rate of Rs 100 per sq. m.
Answers
Answered by
0
Answer:
₹528
Step-by-step explanation:
Given details are
, Length of room = 4.5m
Breadth of wall = 3m
Height of wall = 350cm
= 350/100 = 3.5m
Area of ceiling = l × b
= 4.5 × 3 = 13.5 m2
Area of walls = 2 (lh + bh)
m2 = 2 (4.5×3.5 + 3×3.5) = 2 (15.75 + 10.5) = 52.5 m2
Sum of Area of ceiling + area of walls = 13.5m2 + 52.5m2 = 66m2 Given, Cost for plastering 1m2 area = Rs 8
∴ Cost for plastering 66 m2 area = 66 × 8
= Rs 528
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Answered by
0
Answer:
step 1 : to find it we must add CSA of the room with the area of the ceiling
step 2 : formula
2(l+b)h + l × b
step 3 : length = 9m
breadth = 6 m
height = 4m
calculation:
2 ( 9 + 6 )× 4 + 9×4
2 × 15 × 4 + 36
120 + 36
=
cost of plastering 1 metre = 100 rs
156 ×100 = 15600 rs
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