Question

9. The walls and ceiling of a room are to be plastered. The length, breadth
and height of the room are 9 m, 6 m and 4 m respectively. Find the cost of
plastering at the rate of Rs 100 per sq. m.

Answer 1

Answer:

₹528

Step-by-step explanation:

Given details are

, Length of room = 4.5m

Breadth of wall = 3m

Height of wall = 350cm

= 350/100 = 3.5m

Area of ceiling = l × b

= 4.5 × 3 = 13.5 m2

Area of walls = 2 (lh + bh)

m2 = 2 (4.5×3.5 + 3×3.5) = 2 (15.75 + 10.5) = 52.5 m2

Sum of Area of ceiling + area of walls = 13.5m2 + 52.5m2 = 66m2 Given, Cost for plastering 1m2 area = Rs 8

∴ Cost for plastering 66 m2 area = 66 × 8

= Rs 528

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Answer 2

Answer:

step 1 : to find it we must add CSA of the room with the area of the ceiling

step 2 : formula

2(l+b)h + l × b

step 3 : length = 9m

breadth = 6 m

height = 4m

calculation:

2 ( 9 + 6 )× 4 + 9×4

2 × 15 × 4 + 36

120 + 36

=

${156m}^{2}$

cost of plastering 1 metre = 100 rs

156 ×100 = 15600 rs