Question

9. The zeroes of the quadratic polynomial
3x2 - 48 are
a)both positive
b)both negative
c)both equal
d)one positive one negative​

Answer 1

Step-by-step explanation:

x²=16

x=±4

The answer will be d

Answer 2

$Given \: Quadratic \: polynomial \\p(x) = 3x^{2} - 48$

$Finding \: zeroes \: of \: p(x) , is \:the \:same \\</p><p>as \: solving \: the \: equation \: p(x) = 0$

$As \: 3x^{2} - 48 = 0$

$\impliea 3x^{2} = 48$

$\implies x^{2} = \frac{48}{3}$

$\implies x^{2} = 16$

$\implies x = \pm \sqrt{4^{2}}$

$\implies x = \pm 4$

$\implies x = -4 \:Or \: x = 4$

Therefore.,

$Option \: \pink { ( d ) } \: is \: correct.$

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