Question

9 to the power 2 n-4 to the power 2 n is divisible by

Answer 1

Answer:

9^2n, for n greater than or equal to 1 always results in a number whose least significant digit is 1. in other words the resulting number ends with the digit 1

likewise 4^2n for all values of n equal to greater than 1 always results in numbers ending with 6

So 9^2n = 10x+1 and 4^2n = 10y +6, where x and y are positive non-zero integers and x will be always great than y

9^2n - 4^2n = (10x+1) - (10y + 6) = (10x +11 -10) - 10y -6

= 10(x-1 -y) +5

Step-by-step explanation:

Answer 2

Answer:

3^n

Step-by-step explanation:

9^2n+2n-4

9^4n-4

6561^n-1

ans. 3^n