9. triangleABC ~trianglePQR, if A = 50° then Q + R =
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Answer:
130 Degree
Step-by-step explanation:
If ∆ABC~∆PQR
A=P
B+C=Q+R
A=50
We Know That
A+B+C=180(∆Property)
50+B+C=180
B+C=180-50
Q+R=130(Q+R=B+C)
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