Physics, asked by vinod8874000508, 1 month ago

9. Two blocks of mass mj = 1 kg and m2 = 2 kg are placed in contact on a frictionless horizontal surface. A force of 10 N is acting on my. What is the acceleration produced in my and my?​

Answers

Answered by NewGeneEinstein
1

Formula:-

Newtons 2nd law

\boxed{\sf Force=Mass\times Acceleration}

Case-1

  • Mass=1kg
  • Force=10N

\\ \sf\longmapsto Force=Mass\times Acceleration

\\ \sf\longmapsto Acceleration=\dfrac{Force}{Mass}

\\ \sf\longmapsto Acceleration=\dfrac{10}{1}

\\ \sf\longmapsto Acceleration=10m/s^2

Case-2

  • Mass=2kg
  • Force=10N

\\ \sf\longmapsto Acceleration=\dfrac{Force}{Mass}

\\ \sf\longmapsto Acceleration=\dfrac{10}{2}

\\ \sf\longmapsto Acceleration=5m/s^2

Answered by juwairiyahimran18
0

Formula:-

Newtons 2nd law

\boxed{\sf Force=Mass\times Acceleration}

Case-1

Mass=1kg

Force=10N

\begin{gathered}\\ \sf\longmapsto Force=Mass\times Acceleration\end{gathered}  \\  \\ \begin{gathered}\\ \sf\longmapsto Acceleration=\dfrac{Force}{Mass}\end{gathered}  \\  \\ \begin{gathered}\\ \sf\longmapsto Acceleration=\dfrac{10}{1}\end{gathered}  \\  \\ \begin{gathered}\\ \sf\longmapsto Acceleration=10m/s^2\end{gathered}

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