Question

9. Two buses start from the same bus stand at 8 a.m.
One travels at 40 km/h and the other at 50 km/h.
The second bus reaches the next stop at 10 a.m.
How much later will the first bus arrive?
plz tell me i cant understand that ​

Answer 1

Answer:

30 mins

Step-by-step explanation:

their speed ratio = 40:50 = 4 : 5

speed is inversely proportional to time so their ratio of time taken will be = 5 : 4

let constant ratio be x .

time taken by second bus to reach the next stop = 2 hrs , 4x = 2 => x = 1/2

time taken by first bus = 5x = 5 * 1/2

= 2 hrs 30 mins

so the first bus will arrive = 2h30 mins - 2 hr = 30 mins later

Answer 2

Answer:

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