Question

9.
Two chords AB and AC of a circle with centre o
are on the opposite sides of OA. If angle AOB= angle AOC
then prove that AB = AC and angle OAB = angle OAC (3)​

Answer 1

Answer:Consider the triangles AOC and AOB: AO = AO (Common side in both triangles) OB = OC (Both OB and OC are radius of circle) But we can’t show that either the third side of both triangles are equal or any angle is equal. Therefore ΔAOB is not congruent to ΔAOC. ∴ ∠OAB ≠ ∠OAC

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