Math, asked by abhayje1981, 3 months ago


9. Two cross roads, each of width 5m, run at right angles through the centre of a rectangular
park of length 700 m and breadth 300 m parallel to its sides. Find the area of the roads. Also,
find the cost of constructing the roads at the rate of 105 per m​

Answers

Answered by mathdude500
5

Given Question :-

  • Two cross roads, each of width 5 m, run at right angles through the centre of a rectangular park of length 700 m and breadth 300 m parallel to its sides. Find the area of the roads. Also, find the cost of constructing the roads at the rate of 105 per m^2.

\large\underline\purple{\bold{Solution :-  }}

\tt \:  Length  \: of  \: rectangular \:  field, l= \: 700 \: m

\tt \:Width  \: of  \: rectangular \:  field, b= \: 300 \: m

 \tt \red{Length  \: of  \: the  \: shorter \:  path, l_1= \: 300 \: m}

 \tt \:  \red{</p><p>Width \:  of \:  the  \: shorter  \: path, b_1=5 \: m}

 \tt \:  \purple{Length  \: of \:  the \:  longer \:  path, l_2=700 \: m}

\tt \purple{ Width  \: of  \: the \:  longer \:  path,  \: b_2=5 \: m \:  }

 \tt \green{Area  \: of  \: shorter \:  path,  \: A_1=l_1×b_1}

\tt\implies \:A_1 \:  = 300 \times 5

\tt\implies \: \boxed{ \red{ \bf \: A_1 = 1500 \:  {m}^{2} }}

 \tt \pink{Area  \: of  \: longer  \: path, \:  A_2=l_2×b_2}

\tt\implies \:A_2 \:  =  \: 700 \times 5

\tt\implies \: \boxed{ \red{ \bf \: A_2 = 3500 \:  {m}^{2} }}

 \tt \blue{Thus, Area  \: of \: roads, A_3=A_1+A_2−Area \:  of \:  common \:  path}

\tt\implies \:A_3 \:  =  \: 3500 + 1500 - 5 \times 5

\tt\implies \:A_3 = 5000 - 25

\tt\implies \: \boxed{ \red{ \bf \: A_3 = 4975 \:  {m}^{2} }}

 \tt \green{Now,  \: cost  \: of \:  constructing \:  the  \: roads \: }

\tt\implies \: cost \:  of \:  constructing \:  roads \:  = 4975 \times 105

\tt\implies \: \boxed{ \red{ \bf \: \: Cost = Rs  \: 522375}}

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