Question

9. Two lines AB and CD intersect at O. If AOC = 50°,
find AOD, BOD and BOC.​

Answer 1

Answer:

/_AOD=130° , /_BOD=50° and /_BOC=130°

Step-by-step explanation:

Given:

/_AOC=50°

/_BOD=/_AOC. [Vertically opp. angles]

.°./_BOD=50°

Now, AB is a straight line & transversal OC stand on it...

/_AOC+/_BOC= 180° [Linear Pair]

50°+/_BOC=180°

/_BOC=(180-50)°

.°./_BOC=130°

/_AOD=/_BOC. [ Vertically opp. angles]

.°./_AOD=130°

I hope it will help you!

Answer 2

Answer:

Given : AOC = 50°

BOD = AOC = 50° ( Vertically Opposite Angle)

Since CD is a straight line and is intercepted

by AB,

AOC + AOD = 180° ( Linear Pair)

or, 50° + AOD = 180°

or, AOD = 180° - 50°

or, AOD = 130°

BOC = AOD = 130° ( Vertically Opposite Angle)