Question

9. Two ropes 16 m and 20 m long are to be cut into small pieces of equal length. What will be the maximum length of each piece? 210m​

Answer 1

Answer:

Correct option is  

4m

16=2×2×2×2

20=2×2×5

Maximum length of the piece that has to be cut=H.C.F of 16m and 20m

Now HCF of 16 and 20 is 4

∴ Required length=4m