Question

9. Using algebraic identity, calculate (ii) 403 × 403​

Answer 1

Explanation:

ive given all list

Standard Algebraic Identities List

Identity I: (a + b)2 = a2 + 2ab + b2

Identity III: a2 – b2= (a + b)(a – b)

Identity IV: (x + a)(x + b) = x2 + (a + b) x + ab.

Identity V: (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca.

Identity VI: (a + b)3 = a3 + b3 + 3ab (a + b)

hpoe u got the answer

I've given all list

Answer 2

Answer:

162409

Explanation:

consider 403 x 403

⇒ (403)²

⇒ (400+3)²

using the identity, (a+b)² = a² + b² + 2ab,

⇒ (400)² + (3)² + (2).(3).(400)

⇒ 160000 + 9 + 2400

⇒ 162409

.: (403)(403) = 162409