Question

9. Varun's mother is five times as old as Varun. If sum of their ages is 48 years, find their
10. The sum of three consecutive integers is 24. Find the integers.
ages
The age of Nisha and her mother together is 72. If the mother's age is 3 times that of Nisha, i
11 The​

Answer 1

Step-by-step explanation:

9.let the age of varun be x

and age of mother be 5x

as per question,

sum of their age is 48

so, age of varun+age of his mother=48

that means,

x+5x=48

6x=48

x=48/6

x=8

hence age of varun is 8 year

and age of mother is 5×8=40

10.let the first consecutive number be x

second consecutive number be x+1

third consecutive number be x+2

according to question,

sum of three consecutive number is 24

therefore,

x+(x+1)+(x+2)=24

3x+3=24

3x=24-3

3x=21

x=21/3

x=7

hence first number is 7

second number is 8

and third number is 9

11.let the age of Nisha be x

age of mother be 3x

as per question,

the of of nisha and her mother together is 72

therefore,

x+3x=72

4x=72

x=72/4

x=18

hence age of Nisha is 18 year

and age of mother is 3×18=54

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Answer 2

Answer :

let ,age of varun be 'x' years.

So, age of varun's mother will be '5x'

By given condition,

$x + 5x = 48\\6x=48\\\\x=\frac{48}{6}\\\\x=8$

Age of varun = x = 8 years

and age of varun's mother = 5x= 40 years.

Answer :

Let,

The 3 consecutive integers be x, x+1, x+2

$\therefore\:x+x+1+x+2=24\\3x +3=24\\3x=21\\x=7$

hence, the 3 consecutive integers are :

x = 7

x + 1 = 7+1 =8

x + 2 = 7+2 = 9

Verification : 7+8+9=24

Answer :

Let,

Age of nisha be 'x' yrs.

so, her mother's age will be '3x'.

sum of their ages is 72.

$\therefore\:x + 3x =72\\4x=72\\\\x=\frac{72}{4}\\\\x=18$

Nisha's age = x = 18 years

Her mother's age = 3x = 54 years

Hope it helps !!