Question

9.verify i) x³+y³=(x+y) (x²-xy+y²). ii)x³-y³=(x-y) (x²+xy+y²​

Answer 1

Step-by-step explanation:

RHS = (x+y) (x² + xy + y²)

= x³ + x²y + xy² + x²y + xy² + y³

= x³ + y³

this is equal to LHS

To prove: x

3

−y

3

=(x−y)(x

2

+xy+y

2

)

Consider the right hand side (RHS) and expand it as follows:

(x−y)(x

2

+xy+y

2

)=x

3

+x

2

y+xy

2

−yx

2

−xy

2

−y

3

=(x

3

−y

3

)+(x

2

y+xy

2

+x

2

y−xy

2

)=x

3

−y

3

=LHS

Hence proved.

Yes, we can call it as an identity: For example:

Let us take x=2 and y=1 in x

3

−y

3

=(x−y)(x

2

+xy+y

2

) then the LHS and RHS will be equal as shown below:

2

3

−1

3

=7 and

(2−1)(2

2

+(2×1)+1

2

)=1(5+2)=1×7=7

Therefore, LHS=RHS

i hope this helps you