Physics, asked by bhailalverms3176, 10 months ago

9.
What happens when
(a) Dilute sulphuric acid is poured on a copper plate?
(b) Iron nails are placed in copper sulphate solution?
Write word equations of the reactions involved.​

Answers

Answered by akhilesh9700
11

Answer:

hope it helps...mark my answer as brainlest answer

.

Explanation:

1)Dilute sulphuric acid is poured on a copper plate?

Answer: Copper does not react with dilute sulphuric acid. So, no reaction takes place when dilute sulphuric acid is poured on a copper plate. But when concentrated sulphuric acid is poured over copper plate, effervescence is observed. This happens because of formation of hydrogen gas.

Cu + H2SO4 → CuSO4 + H2

2)

Iron nails are placed in copper sulphate solution? Write word equations of the reactions involved.

Answer: When iron nails are placed in copper sulphate solution, the blue colour of copper solution is replaced by a light green colour. This happens because iron; being more reactive than copper; displaces copper from copper sulphate and makes iron sulphate.

CuSO4 + Fe → FeSO4 + Cu

Answered by akshayanand2104
2

Hello Friend,

I hope You understand this

Answer:

(i) No reaction occurs when dilute sulphuric acid is poured on a copper plate. However, when concentrated sulphuric acid is poured on a copper plate, hydrogen gas evolves along with the formation of blue coloured copper sulphate crystals. The chemical reaction for the reaction between concentrated sulfuric acid and copper is:

 Cu + H_{2}SO_{4} (conc.)  → CuSO_{4} + H_{2}

ii) Iron being more reactive displaces copper from copper sulphate. In this reaction, the blue colour of copper sulphate fades and there is a deposition of copper on the iron nail.

Fe + CuSO_{4} →  FeSO_{4}  + Cu

Similar questions