Question

9. What is the area of cross-section of a bod
in m2, when it exerts a force of 50 N and
produces a pressure of 2000 Pa? ​

Answer 1

Answer:

0.025 m²

Explanation:

Given:

• Force exerted by the object = 50 Newtons = F
• Pressure exerted by the object = 2000 Pascals = P

To find:

• Area of the cross section of the object = A

Formula:

Force=Pressure×Area

Substituting the above values:

50=2000×A

A=$\frac{50}{2000}$

A=$\frac{1}{40}$

Area = 0.025 m²

The area of cross section in contact with the surface is equal to 0.025 m²

Extra:

• N/m² is the standard unit of pressure

Answer 2

Answer:

Given and Find:

• What is the area of cross-section of a bod in m2, when it exerts a force of 50 N and produces a pressure of 2000 Pa?

Using formula:

• Force = Pressure × Area

Calculations:

⇢ 50 = 2000 × Area

⇢ 50/2000

⇢ 1/40

⇢ 0.025 m²

Therefore, 0.025 cm³ is the area of cross-section.