Question

9) What is the molarity of the solution obtained by diluting 13.9 ml of 18 M H SO, to 100 ml?
Answer it

Answer 1

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Answer 2

Given that:

Molarity of H2SO4 M1= 18 M

The volume of H2SO4 V1 =13.9ml

Second volume V2 = 100 ml

To find:

M2 - molarity of the 100ml solution

Solution:

The molarity of the solution obtained by diluting 13.9 ml of 18 M H2SO4 to 100 ml can be calculated by using a simple formula of molarity of mole concept:

Molarity:

• It is the molar concentration for a particular chemical compound in a solution.
• This concentration is measured as the number of moles of solute present per liter of the solution.
• The SI unit concerning the definition of molarity is moles/liter.
• It is denoted by M.
• It is expressed as M = n/v [ where n is the number of moles of solute and v is the volume of the solution in liters.

Relation between the polarity and volume of the solution:

• The product of the molarity and volume of the first solution is equal to the product of molarity and volume of the second solution.
• [M1 V1 = M2 V2] -->equation 1

Putting the values of M1, V1 & V2 in Equation 1 to find the molarity of the solution M2, we get

M1V1 = M2V2

=> 18×13.9 = M2×100

=> 250.2 = M2 × 100

=> M2 = 250.2/100

=>M2 = 2.502

Therefore, the molarity of the solution is 2.502M.