Question

9
What is the potential difference across the
2 resistor in the circuit
6V
shown below?
(A) 1 V
192
(B) 2 V
292
(C) 6 V
(D) 12 V
322​

Answer 1

Explanation:

In the figure given

let voltages at A,B,C,D be V

A

,V

B

,V

C

,V

D

.

Let V

A

>V

B

.

given V

A

−V

B

=16V

let current from A to B be

′

i

′

(through r1,r4,r5)

let current from C to D through r2 be i

1

, then current from r3 will be i−i

1

from C to D.

On applying 'Kirchhoff's voltage law' in the closed loop with 9V source :-

9−2(i−i

1

)+1i

1

=0

⇒i

1

=

3

2i−9

.....(1)

On applying 'Kirchhoff's voltage law' from A to B:-

V

A

−4i−9−1i

1

+3−1i−3i−V

B

=0

⇒16−8i−6−i

1

=0 (∵V

A

−V

B

=16)

⇒30−26i+9=0(∵ from equation (1))

⇒i=1.5A

⇒i

1

=−2A

So current through r1,r4,r5 is 1.5A.

current through r2 is 2A.

current through r3 is 0.5A.

solution

Answer 2

Answer:

answer is b

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