Question

9. What is the power dissipated if 10mA current flows through a 10Kilo-ohm resistor?​

Answer 1

Answer:

According to Ohm’s power equations, P=(I^2)R.

So, I=4 mA, or 0.004A, and R=5 Kohm, or 5000 ohms.

Plugging in the values, P=(.004^2)5000, or P=0.000016x5000, thus P=0.08W or 80 mW.