Question

9. What least number must be added to 1056 to get a number exactly divisible by 23?

Answer 1

VERIFIED

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$Correct \: Answer \: is \: 2$

$⇒ When \:we \:do \: division\: of \: 1056÷23, \\ we \: get \: 21 \: as \: a \: remainder.$

$⇒ So, \: 23−21=2 \\ must \: be \: added \: to \: 1056 \: \\ in \: \: order \: to \: sum \: \\ \: completely \: divisible \:by \: 23.$

$∴ 1056+2=1058$

$∴ The \: least \: number \: should \: be \: added \: to \: 1056, \: so \: that \\ \\ the \: sum \: is \: completely \: divisible \: by \: 23 \: is \: 2.$

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Answer 2

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Answer is 2

So, 2 must be added to 1056

 in order to make the sum completely divisible by 23.

Now,

we can see that when 1058 is divided by 23 we get 46 as quotient and 0 as remainder.

∴ The least number that should be added to 1056,

so that the sum is completely divisible by 23 is 2.