Question

9)
When a p.d. of 3 V is applied between the two ends of a 60 cm long metallic wire.
Current density in it is found to be 1 x 10-7 A/m². Find the conductivity of the
material of the wire in SI system​

Answer 1

Explanation:

Given: V=3V

Length =60cm =0.60m

J=1×10−7A/m2

E=dV

=0.603=5V/m

We know, J=σE

1×10−7=σ×5

σ=2×10−8(Ωm)−1.

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