Question

9
When a sample of HI is warmed to a particular temperature the equilibrium below is established.
2HI(g) + H2(g) + 12(g)
At this temperature, it is found that the partial pressure of HI(g) is 28 times the partial pressure of
H2(g)
What is the value of Kp at this temperature?
A 1.28 x 10-3
B 0.035
C 28
D 784​

Answer 1

Answer:

Let x be the partial pressure of H

2

.

Since number of moles of H

2

= No. of moles of I

2

Therefore,

p

H

2

=p

I

2

=x

∵p

HI

=28×p

H

2

(Given)

∴p

HI

=28x

Therefore,

K

p

=

p

HI

p

H

2

×p

I

2

⇒K

p

=

(28x)

2

x×x

⇒K

p

=1.28×10

−3