Question

9. Which of following set is equivalent to set
x = {x | x2 - 11x + 30 = 0,XER}
(A) Set of all the letters of word 'SMALL'
(B) Set of all even prime numbers.
(C) Set of all integers greater than 4 less
than 8
(D) Set of all non-zero integer whose
modulus is less than 2.​

Answer 1

Answer:

 43∈ Q

43 belongs to set Q.

(ii) -2∉ N

-2 does not belongs to set N.

(iii) P = {p  |  p is an odd number}

P is a set of p such that p is an odd number.

Answer 2

Set of all integers greater than 4 less than 8

Given:

x = {x | x2 - 11x + 30 = 0,XER}

To Find:

The set is equivalent to set x = {x | x2 - 11x + 30 = 0,XER}

Solution:

Let us take the equation,

x2 - 11x + 30 = 0

Upon simplifying ,

The values of x are,

= (x-6) (x-5)

x = 6,5

Hence, the value 6 and 5 is lesser than 8 and greater than 4

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