Question

9 X + 1 upon 3 square by putting identities​

Answer 1

$\huge\bold\red{SOLUTION}$$\bold\purple{♡FollowMe♡}$

(9x + 1/3 )² = 81x² + 1/9 + 6x

bcz. (a+b)² = a²+b²+2ab

81x² + 6x + 1/9 is the answer

$<marquee>$

HOPE IT HELPS...

Answer 2

Answer:

$(9x + \frac{1}{3} ) {}^{2} \\ = (9x) {}^{2} + (\frac{1}{3} ) {}^{2} + 2 \times 9x \times \frac{1}{3} \\ = 81x {}^{2} + \frac{1}{9} + 6x$