9(x+11+2 (2x+7) 256x+2)+7(1-3) -20
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(1)
Given Equation is √3x^2 + 11x + 6√3 = 0
⇒ √3x^2 + 9x + 2x + 6√3 = 0
⇒ √3x(x + 3√3) + 2(x + 3√3) = 0
⇒ (√3x + 2)(x + 3√3) = 0
⇒ x = -2/√3, -3√3.
(2)
Given Equation is 3x^2 - 2√6x + 2 = 0
⇒ 3x^2 - √6x - √6x + 2 = 0
⇒ √3x(√3x - √2) - √2(√3x - √2) = 0
⇒ (√3x - √2)(√3x - √2) = 0
⇒ x = √2/√3, √2/√3.
Answered by
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To Find:-
Solution:-
Value of x = 119
Verification:-
L.H.S=R.H.S
hence verified
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