Math, asked by yousufkiria, 4 months ago

9/x+15=4/9 solbe the equation

Answers

Answered by archanayadav538
0

Step-by-step explanation:

9/x=4/9-15=-131/9

x=-81/131

Answered by anjalirana5670
0

Answer:

Subtract

1

5

15

15

from both sides of the equation

9

+

1

5

=

4

9

\frac{9}{x}+15=\frac{4}{9}

x9+15=94

9

+

1

5

1

5

=

4

9

1

5

\frac{9}{x}+15{\color{#c92786}{-15}}=\frac{4}{9}{\color{#c92786}{-15}}

x9+15−15=94−15

2

Simplify

Subtract the numbers

Subtract the numbers

9

=

1

3

1

9

\frac{9}{x}=-\frac{131}{9}

x9=−9131

3

Multiply all terms by the same value to eliminate fraction denominators

9

=

1

3

1

9

\frac{9}{x}=-\frac{131}{9}

x9=−9131

9

=

(

1

3

1

9

)

x \cdot \frac{9}{x}=x(-\frac{131}{9})

x⋅x9=x(−9131)

4

Simplify

Cancel multiplied terms that are in the denominator

Re-order terms so that constants are on the left

Combine multiplied terms into a single fraction

9

=

1

3

1

9

9=\frac{-131x}{9}

9=9−131x

5

Multiply all terms by the same value to eliminate fraction denominators

9

=

1

3

1

9

9=\frac{-131x}{9}

9=9−131x

9

9

=

9

1

3

1

9

9 \cdot 9=9 \cdot \frac{-131x}{9}

9⋅9=9⋅9−131x

6

Simplify

Multiply the numbers

Cancel multiplied terms that are in the denominator

8

1

=

1

3

1

81=-131x

81=−131x

7

Divide both sides of the equation by the same term

8

1

=

1

3

1

81=-131x

81=−131x

8

1

1

3

1

=

1

3

1

1

3

1

\frac{81}{{\color{#c92786}{-131}}}=\frac{-131x}{{\color{#c92786}{-131}}}

−13181=−131−131x

8

Simplify

Divide the numbers

Cancel terms that are in both the numerator and denominator

8

1

1

3

1

=

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