Question

9^x+2=720+9^x find value of 4x^1/x​

Answer 1

Answer:

${9}^{x + 2} = 720 + {9}^{x} \\ {9}^{x + 2} - {9}^{x} = 720 \\ {9}^{x} \times {9}^{2} - {9}^{x} = 720 \\ {9}^{x}(81 - 1) = 720 \\ {9}^{x} \times 80 = 720 \\ {9}^{x} = \frac{720}{80} \\ {9}^{x} = 9 \\ {9}^{x} = {9}^{1} \\ x = 1 \\ 4 {x}^{ \frac{1}{x} } \\ = 4( {1})^{ \frac{1}{1} } = 4 \times 1 = 4$