9^x+(27×729^x)^1/3=324
please solve this
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9^x+ (27×729^x)^1/3=324
9^x+ (27^1/3) ×(729^x)^1/3 =324
9^x + 3 × 9^x =324
9^x (1 + 3 ) =324
9^x * 4 = 324
9^x = 324 /4
9^x = 81
9^x = 9^2
by comparing
x = 2
9^x+ (27^1/3) ×(729^x)^1/3 =324
9^x + 3 × 9^x =324
9^x (1 + 3 ) =324
9^x * 4 = 324
9^x = 324 /4
9^x = 81
9^x = 9^2
by comparing
x = 2
subh2613:
thank you so much sir
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