Question

9^x*3^2*(3^x/2)^-2=1/27

Answer 1

Hey friend,
Here is the answer you were looking for:
${9}^{x} \times {3}^{2} ( {3}^{ \frac{x}{2} } )^{ - 2} = \frac{1}{27} \\ \\ we \: can \: also\: write \\ \\ ( {3}^{2} )^{x} \times {3}^{2} \times {3}^{ \frac{x}{ 2} \times - 2 } = \frac{1}{ {3}^{3} } \\ \\ {3}^{2x} \times {3}^{2} \times {3}^{ - x} = {3}^{ - 3} \\ \\ as \: the \: bases \: are \: same \: so \: putting \: the \: powers \: equal \\ \\ 2x + 2 + ( - x) = - 3 \\ \\ 2x - x = - 3 - 2 \\ \\ x = - 5$

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@Mahak24

Thanks...
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