Math, asked by Johannesberg, 1 year ago

9^x ×3^2×(3^-x/2)^-2 = 1/27, find the value of x.

Answers

Answered by OmGupta11
11
[tex] 9^{x} \times 3^{2} \times ( 3^{ \frac{-x}{2} })^{-2} = \frac{1}{27} \\ 3^{2x} \times 3^{2} \times 3^{x} = 27^{-1} \\ 3^{2x+2+x} = 3^{-3} \\ 3^{3x+2} =3^{-3} \\ 3x+2=-3 \\ 3x=-3-2=-5 \\ x= \frac{-5}{3} [/tex]

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