Question

9^x×3^2×(3^-x/2)^-2=1/27, find x

Answer 1

Hey here is your answer

${9}^{x} \times {3}^{2} \times ( {3}^{\farc{ - x}{2}} {)}^{ - 2} = \frac{1}{ 27} \\ \\ { {(3}^{2}) }^{x} \times {3}^{2} \times {3}^{\farc{ - x}{2} \times -2 } = \frac{1}{ 27} \\ \\ {3}^{2x} \times {3}^{2} \times {3}^{x} = \frac{1}{ 27} \\ \\ {3}^{(2x + x + 2)} = {{1}{3}}^{3} \\ \\ {3}^{(3x + 2)} = {3}^{-3} \\ \\ 3x + 2 = -3 \\ \\ 3x = - 3 - 2 \\ \\ 3x = -5 \\ \\ \bf \: x = \frac{-5}{3} \: \: \: answer$

hope this helps you

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