Question

9^x-3^x-8=0.. solve for x
Pls solve it.

Answer 1

Answer:

x=( log (1+ √ 33)- log 2 )/log 3

Step-by-step explanation:

let 3^ x a

a^ 2 -a-8= 0

a= (1+ √ 4*8 )/2

a= (1 +√ 33)/2

replacing

3^ x = (1 +√ 33)/2

taking log both the sides

x log 3 = log (1 +√ 33)/2

x= {log (1 +√ 33)/2 }/log 3

x=( log (1+ √ 33)- log 2 )/log 3

Answer 2

Answer:

(3^2) ^x -3^x -8=0

(3^2x) -3^x -8=0

2x-x-8=0

x-8=0

x=8

hope it helps you.