Question

9 x square - 15 X + 6 = 2 0 completing the square method​

Answer 1

Answer:

9square -15x +16 =20

9square -15x = 20-16

18 -15x = 4

-15x = 4-18

-15x = -14

x = -14/-15

x=14/15

hence this is your answere

Answer 2

$\bf {9x}^{2} - 15x + 6 = 20 \\ \\ \to \tt {9x}^{2} - 15x + 6 - 20 = 0 \\ \to \tt {9x}^{2} - 15x - 14 = 0\\ \\ \to \tt {(3x)}^{2} - 2(3x) \bigg ( \frac{15}{6} \bigg) - {\bigg ( \frac{15}{6} \bigg)}^{2} + {\bigg ( \frac{15}{6} \bigg)}^{2} - 14 = 0 \\ \\\to \tt {\bigg (3x - \frac{15}{6} \bigg)}^{2} - {\bigg ( \frac{15}{6} \bigg)}^{2} - 14= 0 \\ \\\to \tt {\bigg (3x - \frac{15}{6} \bigg)}^{2} - \frac{225}{36} - 14 = 0 \\ \\\to \tt {\bigg (3x - \frac{15}{6} \bigg)}^{2} - {\bigg ( \frac{225}{36} + 14\bigg)}^{} = 0 \\ \\\to \tt {\bigg (3x - \frac{15}{6} \bigg)}^{2} - {\bigg ( \frac{225 + 504}{36} \bigg)}^{} = 0 \\ \\\to \tt {\bigg (3x - \frac{15}{6} \bigg)}^{2} - \frac{726}{36} = 0 \\ \\ \to \tt{\bigg (3x - \frac{15}{6} \bigg)}^{2} - {\bigg ( \frac{ \sqrt{726} }{ \sqrt{36} } \bigg)}^{2} = 0 \\ \\ \to \tt{\bigg (3x - \frac{15}{6} \bigg)}^{2} - \bigg ( \frac{26 \sqrt{50} }{6} \bigg)^{2} = 0 \\ \\\to \tt{\bigg (3x - \frac{15}{6} - \frac{26 \sqrt{50} }{6} \bigg)}^{} {\bigg (3x - \frac{15}{6} + \frac{26 \sqrt{50} }{6} \bigg)}^{} = 0 \\ \\\to \tt \bigg \{ \frac{18x - 15 - 26 \sqrt{50} }{6} \bigg \} \bigg \{ \frac{18x - 15 + 26 \sqrt{50} }{6} \bigg \} = 0 \\ \\\to \tt \frac{1}{6} \bigg \{18x - 15 - 26 \sqrt{50} \bigg \} \bigg \{18x - 15 + 26 \sqrt{50} \bigg \} = 0 \\ \\ \to \tt\bigg \{18x - 15 - 26 \sqrt{50} \bigg \} \bigg \{18x - 15 + 26 \sqrt{50} \bigg \} = \frac{0}{ \frac{1}{6} } \\ \\ \to \sf\bigg \{18x - 15 - 26 \sqrt{50} \bigg \} \bigg \{18x - 15 + 26 \sqrt{50} \bigg \} = 0$

Thus,

• Factors of 9x² - 15x + 6 = 20 are (18x-15 -26√50) and (18x-15+26√50)