Question

9 x square - 3 x minus 2 is equals to zero solve the quadratic equation ​

Answer 1

Answer:

2/3 and -1/3

Step-by-step explanation:

9x^2-3x-2=0 using quadratic formula

(3±√9+72)/18

so (3+9)/18 and (3-9)/18 are roots

so 2/3 and -1/3 are the solutions for the equation

Answer 2

Answer:

The answer is (x - 6)(x + 3)

Step-by-step explanation:

= 9$x^{2}$ - 3x - 2

Follow the identity (x + a)(x + b) = $x^{2}$ + (a + b) + ab

Now multiply the first term's constant with the last term

That is,

= 9 X 2

= 18

Now find factors of 18 which add up to the middle term

18 =(-6) X 3

Middle term

3x = -6x + 3x

    = 3x

a = -6

b = 3

So,

= $x^{2}$ + (-6 + 3) + (-6) X 3

= $x^{2}$ - 6x + 3x + (-6) X 3

Take common

= x(x - 6) + 3(x - 6)

Again take common

= (x + 3)(x - 6)

x + 3 = 0 and x - 6 = 0

x = (-3)            x = 6

After putting x = -3 and x = 6 in the polynomial 9$x^{2}$ - 3x - 2 the value comes zero

That is p(x) = 0(After substituting the values)

Hence proved that (x - 6)(x + 3) are the factors of the polynomial 9$x^{2}$ - 3x - 2