Question

9. x2 + 6x + 5 = 0
11. x2 + 12x + 35 = 0
10. 9x2 – 3x – 2 = 0
12. x2 = 18x – 77. solve quadratic equation pls​

Answer 1

Answer:

$9. \: {x}^{2} + 6x + 5 = 0 \\=>{x}^{2} + x + 5x + 5 = 0 \\ =>x(x+1) + 5(x + 1) \\ = > (x + 1)(x + 5) = 0 \\ = > (x + 1) = \frac{0}{x + 5} \\ = > (x + 1) = 0 \\ = > x = - 1$

$10. \: {9x}^{2} - 3x - 2 = 0 \\ =>{9x}^{2}+ 3x - 6x - 2 = 0 \\ = > 3x(3x + 1) - 2(3x + 1)= 0\\ = > (3x+1)(3x - 2) = 0 \\ = > x = \frac{2}{3}$

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Answer 2

Answer:

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