Math, asked by arnavdeshpande87, 10 months ago


9
ZQPR = 90°, seg PMI seg QR and Q-M-R, PM = 10, QM = 8, find QR.​

Answers

Answered by aakriti05
17

Answer:

20.05

Step-by-step explanation:

as given in triangle PQR , ∠P=90°. it means ΔPQR is a right angle triangle . and PM⊥QR.

given that

PM=10

QM=8

as we know

PM²=QM* MR

⇒(10)²=8*MR

⇒100 = 8*MR

⇒MR = 12.5

so QR = QM+MR

=8+12.5

=20.5

Answered by ankitphanzira
7

Answer:

20.05

Step-by-step explanation

Step-by-step explanation:

as given in triangle PQR , ∠P=90°. it means ΔPQR is a right angle triangle . and PM⊥QR.

given that

PM=10

QM=8

as we know

PM²=QM* MR

⇒(10)²=8*MR

⇒100 = 8*MR

⇒MR = 12.5

so QR = QM+MR

=8+12.5

=20.5

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