Question

90% 11:18 AM
Exam End Time: 01:10 pm
RATNERIATICS
PHYSICS
CHEMISTRY
Duration: 3:00:00 Time Left : 1:54:09
Question No.3
s
The normal to the circle given by x2 + y2 - 6x + 8y - 144 = 0 at (8, 8) meets the circle again at the point
A 2-16
(B) (2,16 )
C) 2.16)
(D) (-2,-16)
A
B
C
D​

Answer 1

Answer:

I wish you all the best for your exam

Answer 2

Answer:

The equation of the circle can be put in center-radius form as:

x

2

+y

2

−6x+8y−144=0⇒(x−3)

2

+(y+4)

2

=169

So, clearly the radius of the circle is 13 and its center is at (3,−4).

So, let the normal at (8,8) meets the circle again at (x

0

,y

0

), then the midpoint of (8,8) and (x

0

,y

0

) is the center (3,−4). Thus,

x

0

=6−8=−2 and y

0

=−8−8=−16

So the required point is (−2,−16). Hence option D is the right answer.