Question

90-[70-{80/4-(12-6/2)/3}]

Answer 1

solved with question step by step

Answer 2

In this problem, we are assuming we have to solve the given expression.

Q. Solve$90-[70-{80/4-(12-6/2)/3}]$

Given: $90-[70-{80/4-(12-6/2)/3}]$

We have to solve the above expression.

By using the Bodmas rule, we are solving the above expression.

As we know that the Bodmas rule is used to remember the order of operations to be followed while solving expressions in mathematics.

Where,

$\begin{array}{l}\mathrm{B}=\text{brackets}\\\mathrm{O}=\text { order of powers or rules } \\\mathrm{D}=\text { division } \\\mathrm{M}=\text { multiplication } \\\mathrm{A}=\text { addition } \\\mathrm{S}=\text { subtraction }\end{array}$

We are solving in the following way:

We have,

$90-[70-{80/4-(12-6/2)/3}]$

$= 90-[70-{80/4-(12-6/2)/3}]\\= 90-[70-{80/4-(12-3)/3}]\\= 90-[70-{80/4-(9)/3}]\\= 90-[70-{80/4-9/3}]\\= 90-[70-{20-9/3}]\\= 90-[70-{20-3}]\\= 90-[70-{17}]\\= 90-[70-17]\\= 90-[53]\\= 90-53\\= 37$

Hence, we get the solution is$37$.