Question

90% and 97% pure acid solution are mixed to obtain 21 liters of 95% pure acid solution. find the quantity of each type of acids to be mixed to form the mixture.

Answer 1

Considering quantity of 95% as 1
Assume quantity of 90% acid be X
So quantity of 97% acid will be 1-X

So 90X + 97(1-X) = 95
So 90X + 97-97X = 95
So 97 - 7X = 95
So 97 - 95 = 7X
So 2 = 7X
So
$x \: = 2 \div7$


Thus quantity of 90% concentrate acid will be 2/7 of total of 95% concentrate acid
And
Quantity of 97% concentrate acid is 1 - 2/7 = 5/7 of total of 95% concentrate acid

Answer 2

Answer:

\huge {\mathcal{\purple{H}\green{e}\pink{y}\blue{!}}}Hey!

Let the given solutions be A and B respectively.

Let X litres of A be mixed with Y litres of B .

Then,

X + Y = 21 ---------(1)

★Quantity of acid in X litres of A = (90% of X ) Litres

=> ( 90/100 × X ) Litres

=> 9X / 10 Litres

★ Quantity of acid in Y litres of B = (97% of Y ) litres

=> ( 97/100 × Y ) Litres

=> (97Y/100) litres

★ Quantity of acid in 21 litres of (A + B) = ( 95% of 21 litres )

=> ( 95/100 × 25) litres

=> ( 399/20 ) litres

Therefore,

9X / 10 + 97Y/100 = 399/20

=> 90X + 97Y = 1995 --------(2)

Multiply equation (1) by 90 we get,

90X + 90Y = 1890 -----------(3)

Subtract equation (3) from equation (2) we get,

90X + 97Y = 1995

90X + 90Y = 1890

----------------------------

7Y = 105.

Y = 105/7 = 15

Putting the value of Y in equation (1)

X + Y = 21

X + 15 = 21

X = 21-15

X = 6

So,

6 litres of 90% solution is mixed with 15 litres of 97% solution.

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