90% and 97% pure acid solution are mixed to obtain 21 litres of 95% acid solution. Find the quantity of each type of acid to be mixed to form the mixture .
Answers
Answered by
438
V1 = volume of 90% solution
V2 = volume of 97% solution
Volume of solution = V1 + v2 = 21 L
Concentration = 95% = (V1 * 90% + V2 * 97%) / 21
so 21 * 95 = 90 V1 + 97 V2
= 90 V1 + 97 (21 - V1) = 97 * 21 - 7 V1
So V1 = 6 L and V2 = 15 L
V2 = volume of 97% solution
Volume of solution = V1 + v2 = 21 L
Concentration = 95% = (V1 * 90% + V2 * 97%) / 21
so 21 * 95 = 90 V1 + 97 V2
= 90 V1 + 97 (21 - V1) = 97 * 21 - 7 V1
So V1 = 6 L and V2 = 15 L
Answered by
403
let the amount of 90% pure solution be x
and 97% pure solution be y (in litres)
so the total amount of acid = 21
x + y = 21 ------------ (1)
total concentration of the solution = 95%
90x + 97y = 95×21
90x + 97y = 1995 ----------- (2)
equation (1) × 97 => 97x + 97y = 2037
equation (2) × 1 => 90x + 97y = 1995
(-) (-) (-)
7x = 42
=> x = 6
from eq (1) we get,
6 + y =21
=>y = 15
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